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For a material with poisons ratio 0.25, the ratio of modulus of rigidity to modulus of elasticity will be
1. 0.4
2. 1.2
3. 2.0
4. 3.6

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Correct Answer - Option 1 : 0.4

Concept:

E = 2G(1 + v)

where E = Modulus of elasticity, G = Modulus of rigidity, ν = Poisons ratio.

Calculation:

Given:

Poisson's ratio, v = 0.25

the ratio of modulus of rigidity to modulus of elasticity = \(\frac{G}{E}\)

\(\frac{G}{E} = \frac{1}{{2\left( {1 + v} \right)}}\)

\(\frac{G}{E} = \frac{1}{{2\left( {1 + 0.25} \right)}}\)

\(\frac{G}{E} = 0.4\)

Hence the required value of the ratio of modulus of rigidity to modulus of elasticity is 0.4.

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