Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
437 views
in Physics by (35.7k points)
closed by

Write an activity to prove that the sum of the potential differences of the bulb is equal to voltage across the combination of the resistors. 

(OR) 

Prove that during series connection potential difference is distributed among the resistors experimentally.

1 Answer

+1 vote
by (40.9k points)
selected by
 
Best answer

Aim:

To prove that the sum of the potential differences of the bulbs is equal to potential difference across the combination of the resistors. 

Materials required : 

1. Bulbs 

2. Voltmeters 

3. Insulated wires 

4. Ammeter 

5. Key

Procedure :

1. Take different bulbs. Using a multimeter measure their resistances. Note them as R1, R2 and R

2. Connect them as shown in figure. 

3. Measure the voltage between terminals of the battery connected to the circuit. 

4. Measure the voltages between the ends of each bulb and note them as V1, V2 and V3 from voltmeters in your notebook.

 5. Compare them.

Observation : 

We notice that the sum of the voltages of the bulbs is equal to voltages across the combination of the resistors.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...