Let a1x + b1y – c = 0 ≃ 2x + 3y – 1 = 0
a2x + b2y + c2 = 0 ≃ 3x – y – 7 = 0
Now comparing their coefficients i.e.,\(\frac{a_1}{a_2}\) and \(\frac{b_1}{b_2}\)
⇒ \(\frac{2}{3}\)≠ \(\frac{3}{-1}
\)
The given lines are intersecting lines.
2x + 3y = 1
3y = 1 – 2x
y = \(\frac{1-2x}{3}
\)
3x – y = 7
y – 3x = - 7
y = 3x - 7
The system of equations has a unique solution (2, – 1).