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in Chemistry by (83.7k points)

State the volume occupied by 40 g of a hydrocarbon – CH4 at s.t.p. if its V.D. is 8.

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V.D. of hydrocarbon = 8

∴ Molecular weigh = 2 x V.D. = 2 x 8 = 16 g

16 g of hydrocarbon occupy at S.T.P. = 22.4.lit

∴ 40 g of hydrocarbon occupy at S.T.P 

= 22.4 x 40/16 = 56 lits.

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