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Show that the angles of an equilateral triangle are 60° each.

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Best answer

Given ΔABC is an equilateral triangle 

AB = BC = CA 

∠A = ∠B (∵ angles opposite to equal sides) 

∠B = ∠C (∵ angles opposite to equal sides) 

⇒ ∠A = ∠B = ∠C = x say 

Also ∠A+∠B + ∠C =180° 

⇒ x + x + x = 180° 

3x = 180°

⇒ x = 180°/3 = 60°

Hence proved.

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