A = {2, 4, 6, 8, 10}; B = {1, 2, 3, 6}
A ∪ B = {2, 4, 6, 8, 10} ∪ {1, 2, 3, 6} = {1,2,3,4,6,8,10}
A ∩ B = {2, 4, 6, 8, 10} ∩ {1, 2, 3, 6} = {2, 6}
(A ∪ B) – (A ∩ B) = {1, 2, 3, 4, 6, 8, 10} – {2,6} = {1,3,4,8,10}
A – B = {2,4, 6, 8, 10} -{1,2, 3, 6}. = {4, 8, 10}
B – A = {1,2, 3, 6}-{2, 4, 6, 8, 10} = {1,3}
(A – B) ∪ (B – A)- {4, 8, 10} ∪ {1,3} = {1,3,4, 8, 10}
Noticed that (A ∪ B) – (A ∩ B) = (A – B) ∪ (B – A)