Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
129 views
in Quadrilaterals by (43.4k points)
closed by

ABCD is a parallelogram AP and CQ are perpendiculars drawn from vertices A and C on diagonal BD (see figure). Show that 1) ΔAPB ≅ ΔCQD ii) AP = CQ

1 Answer

+1 vote
by (42.6k points)
selected by
 
Best answer

Given that □ABCD is a parallelogram. 

BD is a diagonal. 

AP ⊥ BD and CQ ⊥ BD

i) In ΔAPB and ΔCQD 

AB = CD ( ∵ Opp. sides of //gm ABCD) 

∠APB = ∠CQD (each 90°) 

∠PBA = ∠QDC (alt. int. angles for the lines AB and DC) 

∴ ΔAPB ≅ ΔCQD (AAS congruence) 

ii) From (1) ΔAPB ≅ ΔCQD 

⇒ AP = CQ (CPCT)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...