Question

Four carrom board pans are arranged as shown in figure. Radius of the pan is 3 cm each. Then find the area in between of them.

Answer 1

Area in between 4 pans = Area of square ABCD formed by joining their centres – 4 (area of sector)

Now side of square ABCD = 3 + 3 = 6 

Then area of square ABCD = 6 × 6 = 36 cm² 

and now area of sector = \(\frac{x}{360}\) × πr² 

Area of 4 sectors = 4 × \(\frac{90}{360}\) x \(\frac{22}{7}\) × 3 × 3 

= \(\frac{198}{7}\) = 28.3 cm² 

∴ Area in between 4 pans i.e., shaded 

= 36 – 28.3 = 7.7 cm²