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A compound has the following percentage composition by mass, Carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correct to 1 decimal place. The relative molecular mass of this compound is 168, so what is its molecular formula? (H = 1 ; C = 12 ; Cl = 35.5)

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Emprirical formula = CHCl2

Empirical formula mass

Relative molecular mass (given) = 168

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