Question

The length, breadth and height of a cuboid are (log 125 + log 8), (log 1000 – log 10) and log 10 respectively. Find the total surface area of the cuboid.

Answer 1

Length of cuboid (l) = (log 125 + log 8) 

Breadth of cuboid (b) = (log 1000 – log 10) 

Height of cuboid (h) = log 10 

∴ (l) = log (125 × 8)

= log 1000 

= log 10³ = 3 log 10 = 3 

(b) = log 1000 – log 10 

= log \(\frac{1000}{100}\)

= log 100 = log 10² = 2 

(h) = log 10 = 1 

Then total surface area of cuboid 

= 2(lb + bh + lh) 

= 2(3 × 2 + 2 × 1 + 1 × 3) 

= 2 (6 + 2 + 3) 

= 2(11) = 22 square units.