Question

In a triangle ABC, ∠B = π/3 and ∠C = π/4. Let D divides BC internally in the ratio 1 : 3, then sin ∠BAD/sin∠CAD is equal to

(a) 1/√6

(b) 1/3

(c) 1/√3

(d) √2/3

Answer 1

Correct option: (a) 1/√6

Explanation:

In ΔABD, applying since rule, we get