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Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg): 4.97, 5.05, 5.08, 5.03, 5.00, 5.06, 5.08, 4.98,5.04,5.07,5.00. Find the probability that any of these bags chosen at random contains more than 5 kg of flour.

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Total number of bags = 11 

No. of bags with a weight more than 5 kg = 7 

[5.05, 5.08, 5.03, 5.06, 5.08, 5.04, 5.07]

∴ Probability = \(\frac {No.\,of\, favourables}{Total\, No.\,of\,outcomes}\)

P(E) = 7/11

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