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In the adjacent figure, prove that ΔPQX ≅ ΔPRY.

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In ΔPQX, ΔPRY 

Sides QX = RY {Given} 

Sides PX = PY {Given} 

∠PXY = ∠PYX 

180 – ∠PXY = 180° – ∠PYX 

⇒ ∠PXQ = ∠PYR {Angle}

By S – A – S congruence criterion. 

ΔPQX ≅ ΔPRY

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