Question

Two pathways parallel to the length and breadth have been constructed in the centre of the rectangular park whose length is 120 m and breadth is 90 m. If the width of each pathway is 15 m, find out expenditure of flooring on the pathway at the rate ₹ 80 per sq.m,

Answer 1

In the figure ABCD is a rectangular park. 

Length of ABCD = 120 m 

Breadth of ABCD = 90 m 

Width of path = 15 m 

Area of EFGH = length × width 

= 120 × 15 = 1800 sq.m 

Area of MNOP = breadth × width 

= 90 × 15 = 1350 sq.m 

Area of common path = width × width 

= 15 × 15 = 225 sq.m

Area of IJKL = 225 sq.m is included in both EFGH and MNOP paths. 

So, we subtract once. 

Area of the path = Area of EFGH + Area of MNOP 

– Area of IJKL. 

= 1800 + 1350 – 225 = 2925 sq.m 

Cost of flooring per sq.m = ₹ 80 

Cost of flooring per 2925 sq.m. = 2925 × 80 

∴ Expenditure for path flooring = ₹ 2,34,000.