Pressure of steam, p = 8 bar
Dryness fraction, x = 0.8
At 8 bar. From steam tables,
vg = 0.240 m3/kg, hfg = 2046.5 kJ/kg
(i) External work done during evaporation
= pxvg = 8 × 105 × 0.8 × 0.24 N-m
= \(\cfrac{8\times10^5\times0.8\times0.24}{10^3}\) = 153.6 kJ.
(ii) Internal latent heat
= xhfg – external work done
= 0.8 × 2046.5 – 153.6
= 1483.6 kJ.