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If a certain amount of steam is produced at a pressure of 8 bar and dryness fraction 0.8. Calculate : 

(i) External work done during evaporation. 

(ii) Internal latent heat of steam.

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Pressure of steam, p = 8 bar 

Dryness fraction, x = 0.8 

At 8 bar. From steam tables,

vg = 0.240 m3/kg, hfg = 2046.5 kJ/kg

(i) External work done during evaporation

= pxvg = 8 × 105 × 0.8 × 0.24 N-m

\(\cfrac{8\times10^5\times0.8\times0.24}{10^3}\) = 153.6 kJ.

(ii) Internal latent heat 

= xhfg – external work done

= 0.8 × 2046.5 – 153.6 

= 1483.6 kJ.

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