Given the length of a rectangle l = 14 cm
Breadth of a rectangle b = ? cm
Perimeter of the rectangle = 2(l + b) = 3 times of length.
2(14 + b) = 3 x 14
Divide with 2 on both sides,
\(\frac{2(14+b)}{2}=\frac{3\times14}{2}\)
14 + b = 21
Subtract with 14 on both sides.
14 + b – 14 = 21 – 14
Breadth b = 7cm
Area of the rectangle A = l x b = 14 x 7 = 98 sq.cm
