Initial volume of air, V1 = 1.6 m3
Initial pressure of air, p1 = 5 bar = 5 × 105 N/m2
Initial temperature of air, T1 = 100 + 273 = 373 K
Final pressure of air, p2 = 1 bar = 1 × 105 N/m2
Now, initial quantity of air in the tank before discharge
Assuming that system undergoes a reversible adiabatic expansion
where T2 is the final temperature of air in the tank.
T2 = 373 × 0.631 = 235.4 K (i.e., finally in the line)
The final quantity of air remaining in the tank is
With Q = 0, kinetic energy is found from,
= 7.47 × 0.771 × 373 – 2.368 × 0.711 × 235.4 – (7.47 – 2.368) × 1 × 235.4
= 2148.24 – 396.33 – 1201 = 550.9 kJ.