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in Physics by (77.4k points)

A bomber plane moves horizontally with a speed of 500 m/s and a bomb released from it, strikes the ground in 10 sec. Angle at which it strikes the ground wil be (g = 10 m/s2

(a) tan-1 (1/5)

(b) tan (1/5)

(c) tan-1(1)

(d) tan-1 (5)

1 Answer

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Best answer

Correct option  (a) tan-1 (1/5)

Explanation:

Horizontal component of velocity vx = 500 m/s and vertical component of velocity while striking the ground.

∴ Angle with which it strikes the ground

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