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in Algebra by (122k points)
Let `a,lambda,mu in R,` Consider the system of linear equations `ax+2y=lambda 3x-2y=mu` Which of the flollowing statement (s) is (are) correct?
A. If a=-3, then the system has infinitely many solutions for all values of `lambda` and `mu`.
B. If `a ne -3`, then the system has a unique solution for all values of `lambda` and `mu`.
C. If `lambda+mu=0`, then the system has infintiely many solutions for a=-3.
D. If `lambda+mu ne 0`, then the system has no solution for a=-3.

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1 Answer

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by (123k points)
Correct Answer - B::C::D

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