
Given
Length of the rectangular park = 700 m
Breadth of the rectangular park = 300 m
From the question,
PS = 10 m. PQ = 700 m
Area of PQRS = 10 × 700 = 7000m2
AB = 10m, AD = 300m
Area of ABCD = 300 x 10 = 3000m2
KL = 10m, KN = 10m
KLMN = 10 × 10 = 100m2
Area of the two paths = IQRS + ABCD – KLMN
= 7000 + 3000 – 100
= 9900m2
The remaining area of the park = Area of the whole park – Area of the two paths
= 700 × 300 – 9900
= 210000 – 9900
= 200100 q.m.