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in Chemistry by (122k points)
The expression relating mole fraction of solute `(x_(2))` and molarity (M) of the solution is :
(where `rho` is the density of solution and `M_(1) and M_(2)` are the molar masses of solvent and solute, respectively.)
A. `x_(2)=(MM_(1))/(M(M_(1)-M_(2))+rho)`
B. `x_(2)=(MM_(1))/(M(M_(1)-M_(2))-rho)`
C. `x_(2)=(M(M_(1)-M_(2))+rho)/(MM_(1))`
D. `x_(2)=(M(M_(1)-M_(2))-rho)/(MM_(1))`

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