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Let `a_1,a_2,a_3,......` be an A.P. such that `[a_1+a_2+......+a_p]/[a_1+a_2+a_3+......+a_q]=p^3/q^3` ; `p!=q`.Then `a_6/a_[21]` is equal to:

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Let `a_1,a_2,a_3,......` be an A.P. such that `[a_1+a_2+......+a_p]/[a_1+a_2+a_3+......+a_q]=p^3/q^3` ; `p!=q`.Then `a_6/a_[21]` is equal to:
A. `(121)/(1861)`
B. `(11)/(41)`
C. `(121)/(1681)`
D. `(41)/(11)`
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Correct Answer - C
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