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If `int(cos4x+1)/(cotx-tanx)dx=kcos4x+c`, then k= (A) `-1/4` (B) `-1/2` (C) `-1/8` (D) none of these

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If `int(cos4x+1)/(cotx-tanx)dx=kcos4x+c`, then k= (A) `-1/4` (B) `-1/2` (C) `-1/8` (D) none of these
A. `A=-1//4` and B may have any value
B. A`=-1//8` and B may have any value
C. `A=-1/2` and `B=-1//4`
D. `A=B=1/2`
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Correct Answer - B
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