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The correct stability order of the following resonance structure is

(a) (I) > (II) > (IV) > (III) 

(b) (I) > (III) > (II) > (IV) 

(c) (II) > (I) > (III) > (IV) 

(d) (III) > (I) > (IV) > (II)

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Best answer

Correct option (b) (I) > (III) > (II) > (IV) 

Explanation:

(I) has maximum covalent bonds and negative charge on electronegative nitrogen, most stable. III has more covalent bond than both II and IV, III is second most stable. Between II and IV, II is more stable since it has negative charge on nitrogen while IV has negative charge on carbon.

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