The thermal circuit for heat flow in the given composite system (shown in has been illustrated in Thickness :
LA = 3 cm = 0.03 m ; LB = LC = 8 cm = 0.08 m ; LD = 5 cm = 0.05 m
Areas :
AA = 0.1 × 0.1 = 0.01 m2 ;
AB = 0.1 × 0.03 = 0.003 m2
AC = 0.1 × 0.07 = 0.007 m2 ;
AD = 0.1 × 0.1 = 0.01 m2
Heat flow rate, Q :
The thermal resistances are given by
The equivalent thermal resistance for the parallel thermal resistances Rth–B and Rth–C is given by :
Now, the total thermal resistance is given by
(Rth) total = Rth–A + (Rth)eq. + Rth–D
= 0.02 + 0.147 + 0.1 = 0.267