Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
136 views
in Physics by (41.5k points)

It can be shown that for a simple compressible substance, the relationship

cp - cv = - T \(\left(\cfrac{∂V}{∂T}\right)^2_p\)\(\left(\cfrac{∂p}{∂v}\right)_T\) exists

where cp and cv are specific heats at constant pressure and constant volume respectively, T is temperature, V is volume and p is pressure. Which one of the following statements is NOT true ? 

(a) cp is always greater than c

(b) The right side of the equation reduces to R for an ideal gas

(c) Since \(\left(\cfrac{∂p}{∂v}\right)_T\) can be either positive or negative, and \(\left(\cfrac{∂V}{∂T}\right)_p\) must be positive, T must have a sign which is opposite to that of \(\left(\cfrac{∂p}{∂v}\right)_T\)

(d) cp is very nearly equal to cv for liquid water.

Please log in or register to answer this question.

1 Answer

+1 vote
by (47.1k points)

(b) The right side of the equation reduces to R for an ideal gas

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...