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As per the above figure 

1) The end ‘B’ of the rod becomes charged 

2) Electric current flows along the rod from A to B 

3) The end ‘A’ of the rod becomes positively charged 

4) The rod AB is uniformly charged

1 Answer

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Best answer

1) The end ‘B’ of the rod becomes charged / 3) The end ‘A’ of the rod becomes positively charged

F = q\((\overline{V}×\overline{B})\)

A is at positive potential / charge 

B is at negative potential / charge

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