There are two equations provided here.
3x – 5y – 4 = 0
3x -5y = 4 ……. (1).
9x = 2y + 7
9x -2y = 7 ……(2).
We have to solve for x and y in the given equations by the elimination method
Now only considering equations (1) and (2)
3x – 5y = 4………(1)
9x – 2y = 7 ……(2)
On multiplying eq. (1) by 3, we get….
3 (3x – 5y = 4)
9x – 15y = 12…… (3).
Now we can easily subtract (2) and (3) to get…..
9x – 2y = 7
– 9x – 15y = 12.
– +13 y = -5
Or we get 13 y = -5 or y = -5/13.
Now we substitute the value of Y = -5/13 in equation (1) we get the value of x.
3x – 5(-5/13) = 4
3x +25/13 = 4
39x + 25 = 52
Or 39x = 52 – 25
39x = 27
Or x = 27/39 = 9 / 13
So x = 9/13 and y = -5/13.
x = 9/13 and y = -5/13
