Question

Find the largest number that will divide 398 , 436 and 542 leaving remainders 7 , 11 and 15 respectively.

Answer 1

We need to find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11 and 15 respectively. Hence, we need to find the HCF of 3 numbers (398-7), (436-11) and (542-15).

Hence,

398 - 7 = 391

436 - 11 = 425

542 - 15 = 527

Now, you can find the HCF(391, 425, 527) = 17

Hence, the largest number that will divide 398,436 and 542 leaving remainders 7, 11 and 15 respectively is 17.