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If f(x) = |(2cos^2x, sin2x, -sinx), (sin2x, 2sin^2x, cosx), (sinx, - cosx, 0)|, then ∫(f(x) + f'(x))dx for (x = 0, π/2)

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If f(x) = |(2cos2x, sin2x, -sinx), (sin2x, 2sin2x, cosx), (sinx, - cosx, 0)|, then ∫(f(x) + f'(x))dx for (x = 0, π/2)

(a) 1

(b) π

(c) 0

(d) 1/3 - π/2

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The correct option (b) π

Explanation:

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