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निम्न का मान दशमलव के तीन स्थानों तक ज्ञात कीजिए। यदि दिया है: √2= 1.4142, √3 = 1.732, √5 = 2.2360, √6 = 2.4445, √10 = 3.162

\(\frac{1+√2}{3-2√2}\)

(1 + √2)/(3 - 2√2)

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\(\frac{1+√2}{3-2√2}\times\frac{3+2√2}{3+2√2}\)

 = \(\frac{3+2\sqrt2+3\sqrt2+4}{9-8}\)

 = 7 + 5√2 = 7 + (5 x 1.1442)

 = 7 + 7.0710 = 14.0710

⇒ 14.071

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