Question

Cu(s) + Sn²⁺ (0.001M) → Cu²⁺ (0.01M) + Sn(s) 

The Gibbs free energy change for the above reaction at 298 K is x × 10^–1 kJ mol^–1 ; 

The value of x is______. [nearest integer]

Answer 1

= 98333.5 J/mol 

= 98.335 kJ/mol 

= 983.35 × 10^–1 kJ/mol

Nearest Integer: 983