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Time period of a simple pendulum in a stationary g lift is "T". If the lift accelerates with g/6 vertically  upwards then the time period will be: (where g = acceleration due to gravity)

(A) \(\sqrt{\frac65}T\) 

(B) \(\sqrt{\frac56}T\) 

(C) \(\sqrt{\frac67}T\) 

(D) \(\sqrt{\frac76}T\)

1 Answer

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Best answer

Correct option is (C) \(\sqrt{\frac67}T\)

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