Standard entropy of X2 , Y2 and XY3 are 60, 40 and 50 JK^–1 mol^–1, respectively.

Standard entropy of X₂ , Y₂ and XY₃ are 60, 40 and 50 JK^–1 mol^–1, respectively. For the reaction,1/2 X₂ + 3/2 Y₂ → XY₃ ΔH = – 30 kJ. To be at equilibrium the temperature will be :

(A) 500 K

(B) 750 K

(D) 1250 K

Standard entropy of X2 , Y2 and XY3 are 60, 40 and 50 JK^–1 mol^–1, respectively.

Please log in or register to add a comment.

1 Answer

Please log in or register to add a comment.

Find MCQs & Mock Test

Related questions

Categories