It is a geometric progression with common ratio, r=5 ; and first term, a=0.004
the nth term of a geometric progression is given by,
an = a(r)n-1
for the given question we have, an=128
Hence,
128=0.004(5)n-1
32000=5n-1
Taking log with base 5 on both sides
6.445=n-1
n=7.445
Since n is not a natural number we can conclude that 128 is not a term of the series.