We find ZTh by setting the voltage source to zero. As shown in Fig. (a) below, the 8-Ωresistance is now in parallel with the −j6 reactance, sothat their combination gives

Similarly, the 4-Ωresistance is in parallel with the j12 reactance, andtheir combination gives


The Thevenin impedance is the series combination of Z1 and Z2; that is,

To find VTh, consider the circuit in Fig. (b). Currents I1 andI2 are obtained as

Applying KVL around loop bcdeab in Fig.(b) gives
