Question

The relation between velocity and position of a particle is V = Ax + B where A and B are constants. Acceleration of the particle is 10 ms^–2 when its velocity is V, How much is the acceleration when its velocity is 2V. 

(A) 20 ms^–2 

(B) 10 ms^–1 

(C) 5 ms^–2 

(D) 0

Answer 1

Correct option: (A) 20 ms^–2

Explanation:

V = Ax + B

when  V = V, a₁ = 10 m/s² 

when  V = 2V a₂ = ?

a = (dv / dt) = (d / dt) (Ax + B)

= A (dx / dt) = AV

a ∝ V

(a₂ / a₁) = (V₂ / V₁)

a₂ = (10) (2V / V)

a₂ = 20 m/s²