Question

From a group of 10 boys B₁, B₂,..., B₁₀, and 5 girls G₁, G₂,...G₃, the number of ways of selection of group of 3 boys and 3 girls, such that B, & B, are not together in group is _____.

Answer 1

Correct answer is 1120.00

Number of ways to select 3 boys = Total ways - No. of ways when both B₁ & B₂ are selected = 10C₃ -⁸C₁ =112 

Number of ways to select 3 girls = ⁵C₃ = 10

Required number of ways = 112 x 10 = 1120