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The mean and variance of a binomial distribution are α and \(\frac\alpha3\) respectively. If P(X = 1) = \(\frac 4{243}\), then P(X = 4 or 5) is equal to:

(A) \(\frac 59\)

(B) \(\frac{64}{81}\)

(C) \(\frac{16}{27}\)

(D) \(\frac{145}{243}\)

1 Answer

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Best answer

Correct option is (C) \(\frac{16}{27}\) 

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