Let \(\vec{a},\vec{b},\vec{c}\) be three coplanar concurrent vectors such that angles between any two of them is same. If the product of their magnitudes is 14 and \((\vec{a}\times\vec{b}).(\vec{b}\times\vec{c})+(\vec{b}\times\vec{c}).(\vec{c}\times\vec{a})+(\vec{c}\times\vec{a}).(\vec{a}\times\vec{b})\) = 168 then \(|\vec{a}|+|\vec{b}|+|\vec{c}|\) is equal to:
(A) 10
(B) 14
(C) 16
(D) 18
