Consider the reaction
4HNO3(l) + 3KCl(s) → Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s)
The amount of HNO3 required to produce 110.0 g of KNO3 is :
(Given : Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.)
(A) 32.2 g
(B) 69.4 g
(C) 91.5 g
(D) 162.5 g