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Consider the reaction

4HNO3(l) + 3KCl(s) → Cl2(g) + NOCl(g) + 2H2O(g) + 3KNO3(s) 

The amount of HNO3 required to produce 110.0 g of KNO3 is : 

(Given : Atomic masses of H, O, N and K are 1, 16, 14 and 39, respectively.) 

(A) 32.2 g 

(B) 69.4 g 

(C) 91.5 g 

(D) 162.5 g

1 Answer

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Best answer

Correct option is (C) 91.5 g 

4HNO3(l)+3KCI(s)→ Cl2 (g) +NOCI (g) +2H2O(g) +3KNO3(g)

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