A slab of dielectric constant K has the same cross sectional area as the plates of a parallel plate capacitor and thickness 3/4 d, where d is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be :
(Given C0 = capacitance of capacitor with air as medium between plates.)
(A) \(\frac{4KC_0}{3+K}\)
(B) \(\frac{3KC_ 0}{3+k}\)
(C) \(\frac{3+k}{4KC_ 0}\)
(D) \(\frac{k}{4+K}\)
