Question

A solid cylinder rolls down a smooth inclined plane 4.8 m high without slipping what is its linear speed at the bottom of the plane, if it starts rolling from the top of the plane? (take g = 10 m/S²) 

(A) 4 m/S 

(B) 2 m/S 

(C) 10 m/S 

(D) 8 m/S

Answer 1

Correct option: (D) 8 m/S

Explanation:

Given is solid cylinder, rolls down without slipping.

for solid cylinder (k² / R²) = (1/2) where k is radius of gyration also h = 4.8 m

V = √[(2gh) / {1 + (k² / R²)}]

= √[(2 × 10 × 4.8) / {1 + (1/2)}]

= √(48 × 2 × 2) / 3]

= 8 m/S