Question

A hydrogen atom in its ground state is irradiated by light of wavelength 970 Å. Taking hc / e = 1.237 x 10^-6 eV m and the ground state energy of hydrogen atom as -13.6 eV, the number of lines present in the emission spectrum is

Answer 1

Unit of he/e in original paper is incorrect

Energy available E = hc/λ = 1.237 x 10^-6 evm / 970 x 10^-10 m 

= 12 . 75 eV (4^th energy level of hydrogen atom)

Hence, the number of lines present in the emission spectrum = \(^4C_2 =6\)