Question

The height at which the weight of a body becomes 1/16 th its weight on the surface of (radius R) is 

(A) 3R 

(B) 4R 

(C) 5R 

(D) 15R

Answer 1

Correct option: (A) 3R

Explanation:

at height h,   g' = g[R / (R + h)]² 

(g/16) = g[R / (R + h)]² 

∴ [R / (R + h)] = (1/4)

4R = R + h

h = 3R