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A particle of mass M and positive charge Q, moving with a constant velocity u1 = 4\(\hat{i}ms^{-1}\) ,enters a region of uniform static magnetic field normal to the x-y plane. The region of the magnetic field extends from x = 0 to x = L for all values of y. After passing through this region, the particle emerges on the other side after 10 milliseconds with a velocity \(\vec{u}_2\) = 2(\(\sqrt{3}\hat{i}+\hat{j}\)) m/s-1 . The correct statement(s) is (are)

(A) The direction of the magnetic field is -z direction. 

(B) The direction of the magnetic field is +z direction.

(C) The magnitude of the magnetic field \(\frac{50\pi M}{3Q}\) units.

(D) The magnitude of the magnetic field is \(\frac{100\pi M}{3Q}\)

1 Answer

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Best answer

 (A) The direction of the magnetic field is -z direction. 

(C) The magnitude of the magnetic field \(\frac{50\pi M}{3Q}\) units.

So magnetic field is along -ve, z-direction

Time taken in the magnetic field = 10x10-3 = πM/6QB

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