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The following integral \(\int\limits_{\pi /4}^{\pi /2}\) (2 cosec x)17 dx is equal to

(A) \(\int\limits_{0}^{log(1+\sqrt{2})}\) 2(eu + e-u)16 du

(B) \(\int\limits_{0}^{log(1+\sqrt{2})}\) (eu + e-u)17 du

(C) \(\int\limits_{0}^{log(1+\sqrt{2})}\) (eu - e-u)17 du

(D) \(\int\limits_{0}^{log(1+\sqrt{2})}\) 2(eu - e-u)16 du

1 Answer

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(A) \(\int\limits_{0}^{log(1+\sqrt{2})}\) 2(eu + e-u)16 du

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