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Let the equation x + y +z = 5 , x + 2y + 2z = 6, x + 3y + λz =μ have infinite solutions then the value of λ + μ is

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Let the equation x + y +z = 5 , x + 2y + 2z = 6, x + 3y + λz =μ have infinite solutions then the value of  λ + μ is

(1)  7

(2)  10

(3)  11

(4)  1/2

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1 Answer

+1 vote
by (69.2k points)

Correct option  (2) 10

Explanation:

for infinitely many solutions

form (i) and (ii) y + z = 1

x = 4 which satisfy (iii) equation hence there are infinite number of solutions λ + μ = 10

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