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दी गई गुणोत्तर-श्रेणी में T2 = 9 और T5 = 243 हो, तो S4 ज्ञात करो ।

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Tn = a.rn – 1

∴ T2 = a.r2 – 1

∴ 9 = a.r ……………. (i)

T5 = a.r5 – 1

∴ 243 = a.r4……………. (ii)

परिणाम (i) का मान परिणाम (ii) में रखने पर

∴ 243 = ar.r3

∴ 243 = 9.r3

∴ r3 = \(\frac{243}9\)

∴ r3 = 27

∴ r3 = (3)3

∴ r = 3

परिणाम (i) में r = 3 रखने पर

ar = 9

∴ a × 3 = 9

∴ a = \(\frac{9}3\)

∴ a = 3

अब S4 ज्ञात करना है इसलिए a = 3, r = 3

और n = 4 Sn के सूत्र में रखने पर यहाँ |r| > 1 है ।

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