Question

If (λ,2) is an interior point of ΔABC formed by x+y=4, 3x–7y=8 and 4x–y=31 then λε(a, b), the value of 6a+8b must be.

Answer 1

\(\frac{22}{3}<\lambda <\frac{33}{4}\)

\(a=\frac{22}3\), \(b=\frac{33}{4}\)

\([6a+8b=6\times \frac{22}3+8 \times \frac{33}4=44+66]\)

= 44 + 66 = 110